Crypkey License Service
Hi
I am currently packaging Dyadem PHA-Pro 6 and cannot after exhausting all possibilities get this service to remove on uninstall.
The service executable is at c:\windows\system32\crypserv.exe.
I am using installshield.
Anyhelp greatly appreciated.
I am currently packaging Dyadem PHA-Pro 6 and cannot after exhausting all possibilities get this service to remove on uninstall.
The service executable is at c:\windows\system32\crypserv.exe.
I am using installshield.
Anyhelp greatly appreciated.
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Posted by:
MSIMaker
19 years ago
Gee someone better rate me then :)
jk...Hope it works for you oreillyr.
jk...Hope it works for you oreillyr.
Posted by:
wiseapp
19 years ago
Hi Oreilly:
Can this service be manually stopped? in case yes, then you could write a vbscript or a batch script with this line:
net stop servicename
I hope this would help , still you require any clarifications regarding the same kindly revert back.
Can this service be manually stopped? in case yes, then you could write a vbscript or a batch script with this line:
net stop servicename
I hope this would help , still you require any clarifications regarding the same kindly revert back.
Posted by:
MSIMaker
19 years ago
Sounds to me like it is a kernel service.....if it is then a reboot is required to remove it
Place your stop service in the msi but dont remove it and place a custom action in your RUN key to delete the file on system startup.
Once the system restarts the crypserv.exe wont be there to restart.
Place your stop service in the msi but dont remove it and place a custom action in your RUN key to delete the file on system startup.
Once the system restarts the crypserv.exe wont be there to restart.
Posted by:
oreillyr
19 years ago
Thanks to you both.
I have tried what you suggested Bhupesh to no avail.
I will try your suggestion on monday jim asit sounds like it could work.
Thanks again for the prompt replies
I have tried what you suggested Bhupesh to no avail.
I will try your suggestion on monday jim asit sounds like it could work.
Thanks again for the prompt replies
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