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Looking for help to build a custom report for finding software list by system label

I am trying to create a custom report for show me all the software installed on any system with a specific k1000 label attached to it. 


Any SQL report creation help would be appreciated.


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Answers (3)

Answer Summary:
Posted by: KevinG 9 months ago
Red Belt
0

I assume you are referring to devices with a particular device label?


Select

MACHINE.NAME,

SOFTWARE.DISPLAY_NAME,

LABEL.NAME

from MACHINE

join MACHINE_SOFTWARE_JT on MACHINE_SOFTWARE_JT.MACHINE_ID = MACHINE.ID

join SOFTWARE on SOFTWARE.ID = MACHINE_SOFTWARE_JT.SOFTWARE_ID

join MACHINE_LABEL_JT on MACHINE_LABEL_JT.MACHINE_ID = MACHINE.ID

join LABEL on LABEL.ID = MACHINE_LABEL_JT.LABEL_ID

where LABEL.NAME = 'TheLableName'    --- <-- Replace with your label name

Posted by: sbaxter 9 months ago
Purple Belt
0

Top Answer

Kevin,

Yes.. Thank you.. that is VERY VERY close to what I am looking for.. 

The only thing I need to figure out is how to consolidate the created list...

I need it to show the software titles but then the total number of times it is installed within that device label group.

This report shows every system in that label and all the software from each machine.

I'd rather it was software title and there are 5 installs of it in that label. that would make for a much cleaner and shorter list... 

The first one I ran had 2250 lines of software titles over 15 devices.


Comments:
  • Try the following SQL

    Select
    SOFTWARE.DISPLAY_NAME,
    COUNT(*)
    from MACHINE
    join MACHINE_SOFTWARE_JT on MACHINE_SOFTWARE_JT.MACHINE_ID = MACHINE.ID
    join SOFTWARE on SOFTWARE.ID = MACHINE_SOFTWARE_JT.SOFTWARE_ID
    join MACHINE_LABEL_JT on MACHINE_LABEL_JT.MACHINE_ID = MACHINE.ID
    join LABEL on LABEL.ID = MACHINE_LABEL_JT.LABEL_ID
    where LABEL.NAME = 'TheLableName'
    group by SOFTWARE.DISPLAY_NAME

    Replace "TheLabelName" with your label name. - KevinG 9 months ago
Posted by: sbaxter 9 months ago
Purple Belt
0


Thank you so much Kevin...  I'm obviously not an SQL guy but this is exactly what I was looking for!!!! 


Comments:
  • Glad to help! - KevinG 9 months ago

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